What Is The Mass Of 3.35 Mol Hg(Io3)2

The molar mass of Hg(IO3)2 (mercury(II) iodate) can be calculated by summing the atomic masses of its constituent elements:

molar mass = 2(molar mass of I) + molar mass of Hg + 6(molar mass of O)

= 2(126.90 g/mol) + 200.59 g/mol + 6(15.99 g/mol)

= 652.45 g/mol

To calculate the mass of 3.35 mol of Hg(IO3)2, we can use the following formula:

mass = number of moles x molar mass

= 3.35 mol x 652.45 g/mol

= 2185.08 g

Therefore, the mass of 3.35 mol of Hg(IO3)2 is approximately 2185.08 grams.