What Is The Molar Mass Of Iron (III) Phosphate?

The molar mass of iron (III) phosphate can be calculated by adding the atomic masses of each element in one mole of the compound. Iron (III) phosphate has the chemical formula FePO4, which indicates that it contains one iron atom (Fe), one phosphorus atom (P), and four oxygen atoms (O).

The atomic mass of iron is 55.845 g/mol, the atomic mass of phosphorus is 30.974 g/mol, and the atomic mass of oxygen is 15.999 g/mol. Therefore, the molar mass of FePO4 can be calculated as follows:

Molar mass of FePO4 = (1 x 55.845) + (1 x 30.974) + (4 x 15.999)

= 55.845 + 30.974 + 63.996

= 150.815 g/mol

Therefore, the molar mass of iron (III) phosphate is 150.815 g/mol.