What Is The Molecular Weight Of Fe3(PO4)2?

The molecular weight of Fe3(PO4)2 is calculated by adding the atomic weights of all the atoms in one molecule.

Fe3(PO4)2 contains 3 iron atoms, 2 phosphorus atoms, and 8 oxygen atoms.

The atomic weight of iron (Fe) is 55.845 g/mol, the atomic weight of phosphorus (P) is 30.974 g/mol, and the atomic weight of oxygen (O) is 15.999 g/mol.

Therefore, the molecular weight of Fe3(PO4)2 can be calculated as follows:

3 x 55.845 g/mol (for the iron atoms) + 2 x 30.974 g/mol (for the phosphorus atoms) + 8 x 15.999 g/mol (for the oxygen atoms) = 357.724 g/mol

Hence, the molecular weight of Fe3(PO4)2 is 357.724 g/mol.