What Is The Molarity Of A Solution Of Sodium Sulfate That Contains 5 Grams Per Liter?

The molarity of a solution of sodium sulfate that contains 5 grams per liter can be calculated as follows:

1. Determine the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol.

2. Convert the mass of the solute (5 grams) to moles by dividing by the molar mass:

5 g ÷ 142.04 g/mol = 0.0353 mol

3. Calculate the volume of the solution in liters. Since the concentration is given in terms of grams per liter, we know that there are 5 grams of sodium sulfate in each liter of solution. Therefore, the volume of the solution is also 1 liter.

4. Finally, divide the number of moles of solute by the volume of the solution in liters to obtain the molarity:

0.0353 mol ÷ 1 L = 0.0353 M

Therefore, the molarity of the solution is 0.0353 M.