What Is The Lewis Structure Of Xenon Tetrafluoride?

The Lewis structure of xenon tetrafluoride (XeF4) can be determined by first calculating its total number of valence electrons, which is 36 (8 from xenon and 7 from each fluorine atom).

Next, arrange the atoms in a symmetrical layout with the xenon atom in the center, surrounded by four fluorine atoms, each bonded to xenon with a single bond.

Then, place the remaining 16 valence electrons as lone pairs around the fluorine atoms to satisfy their octet rule. Each fluorine should have three lone pairs of electrons and one single bond to xenon. The xenon atom will have two lone pairs of electrons.

The final Lewis structure for XeF4 should show four single bonds between xenon and fluorine, with each fluorine having three lone pairs and the xenon atom having two lone pairs.