Xeo4 Hybridization

The hybridization of XeO4 can be determined by first drawing the Lewis structure for the molecule. The central xenon atom is surrounded by four oxygen atoms, each of which forms a double bond with the xenon and has two lone pairs of electrons.

Based on this arrangement, we can determine that the hybridization of the central xenon atom is sp3d2. This means that the xenon atom's valence orbitals are combined to form six hybrid orbitals, which are oriented in an octahedral geometry around the central atom.

In sp3d2 hybridization, one s orbital, three p orbitals, and two d orbitals combine to form six equivalent hybrid orbitals. The resulting hybrid orbitals have a trigonal bipyramidal arrangement, with three of the hybrid orbitals pointing towards the corners of a triangle and the other two pointing perpendicular to this plane.

Overall, the hybridization of XeO4 is sp3d2, which results in an octahedral geometry around the central xenon atom, with four oxygen atoms arranged symmetrically around it.